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$∣ (a, b) ∣ = a^{2} + b^{2}$

Att ta absolutbeloppet av en vektors koordinater är samma sak som att beräkna vektorns längd. Vektorn $v = (1, 2)$ har alltså längden $∣ (1, 2) ∣ = 1^{2} + 2^{2} = 5 le .$ Detta kan motiveras med Pythagoras sats.

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