$a

b^{\log_{b}(a)}

= U t t r y c k e t

b^{\log_b(a)}

k a n f \overset{o}{¨} r e n k l a s t i l l

a,

m e n d e t t a g \overset{a}{¨} l l e r \overset{a}{¨} v e n \overset{a}{˚} t a n d r a h \overset{a}{˚} l l e t . E t t t a l k a n a l l t s \overset{a}{˚} s k r i v a s s o m e n p o t e n s d \overset{a}{¨} r b a s e n \overset{a}{¨} r

b

o c h [[E x p o n e n t * W o r d l i s t * ∣ e x p o n e n t e n]] \overset{a}{¨} r e n [[L o g a r i t m * W o r d l i s t * ∣ l o g a r i t m]] m e d s a m m a b a s

b,

a.

M a n k a n s \overset{a}{¨} g a a t t "

b

u p p h \overset{o}{¨} j t t i l l " o c h "

\log_b$" tar ut varandra.