Mega 2.13 Fredrik

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Solve the following equation. $\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}$

$z=\text{-}4$

To solve the equation, we need to transfer the

z

terms to one side and the constant terms to the other.

\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}

\text{VL}-\dfrac{1}{2}=\text{HL}-\dfrac{1}{2}

\text{-} \dfrac{6}{2}=\dfrac{3}{4}z

Beräkna kvot

\text{-}3=\dfrac{3}{4}z

\left.\text{VL}\middle/3\right.=\left.\text{HL}\middle/3\right.

\text{-}1=\dfrac{1}{4}z

\text{VL} \cdot 4=\text{HL}\cdot 4

\text{-}4=z

Omarrangera ekvation

z=\text{-}4

The solution of the equation then is

z=\text{-}4.