Exercise

Solve the following equation. $\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}$

Answer

$z=\text{-}4$

Solution

To solve the equation, we need to transfer the $z$ terms to one side and the constant terms to the other.

$\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}$

$\text{VL}-\dfrac{1}{2}=\text{HL}-\dfrac{1}{2}$

$\text{-} \dfrac{6}{2}=\dfrac{3}{4}z$

Beräkna kvot

$\text{-}3=\dfrac{3}{4}z$

$\left.\text{VL}\middle/3\right.=\left.\text{HL}\middle/3\right.$

$\text{-}1=\dfrac{1}{4}z$

$\text{VL} \cdot 4=\text{HL}\cdot 4$

$\text{-}4=z$

Omarrangera ekvation

$z=\text{-}4$

The solution of the equation then is $z=\text{-}4.$