## Exercise

Solve the following equation. $\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}$

$z=\text{-}4$

## Solution

To solve the equation, we need to transfer the $z$ terms to one side and the constant terms to the other.
$\text{-} \dfrac{5}{2}=\dfrac{3}{4}z+\dfrac{1}{2}$
$\text{-} \dfrac{6}{2}=\dfrac{3}{4}z$
$\text{-}3=\dfrac{3}{4}z$
$\text{-}1=\dfrac{1}{4}z$
$\text{-}4=z$
$z=\text{-}4$
The solution of the equation then is $z=\text{-}4.$