Exercise

Solve the following equation. $3(3m-2)=2(3m+3)$

Solution

To solve the equation, we begin by distributing the coefficients in front of both parentheses. Then, we manipulate the expression to get $m$ by itself on one side. Then we begin to solve for $m$.

$3(3m-2)=2(3m+3)$

Multiplicera in koefficient

$9m-6=6m+6$

$\text{VL}+6=\text{HL}+6$

$9m=6m+12$

$\text{VL}-6m=\text{HL}-6m$

$3m=12$

$\left.\text{VL}\middle/3\right.=\left.\text{HL}\middle/3\right.$

$m=4$

Then the solution to the equation is $m=4$.