Mega 1.6 Ferenc

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Exercise 6
Solve the following equation.

3 (3 m - 2) = 2 (3 m + 3)

$m = 4$

Start with expanding the expressions on both sides.

We need to find the value of

m

for which the two sides evaluate to the same number. We start with expanding the expressions on both sides of the equality.

3 (3 m - 2) = 2 (3 m + 3)

Multiplicera in $3 & 2$

9 m - 6 = 6 m + 6

Next we use inverse operations to isolate

m .

9 m - 6 = 6 m + 6

$VL - 6 m = HL - 6 m$

9 m - 6 m - 6 = 6

$VL + 6 = HL + 6$

9 m - 6 m = 12

LHS: Bryt ut $m$

(9 - 6) m = 12

LHS: Förenkla termer

3 m = 12

$VL / 3 = HL / 3$

m = 4

Hence, the value that makes the equality true is

m = 4 .