## Question

{\displaystyle \begin{aligned} \textbf{MEGA Practice #1} \end{aligned}}
Exercise 6
Solve the following equation. \begin{aligned} 3(3m-2)=2(3m+3) \end{aligned}

$m=4$

## Solution

We need to find the value of $m$ for which the two sides evaluate to the same number. We start with expanding the expressions on both sides of the equality.
$3(3m-2)=2(3m+3)$
$9m-6=6m+6$
Next we use inverse operations to isolate $m.$
$9m-6=6m+6$
$9m-6m-6=6$
$9m-6m=12$
$(9-6)m=12$
$3m=12$
$m=4$
Hence, the value that makes the equality true is $m=4.$