Question

$$\begin{aligned} \textbf{MEGA Practice #1} \end{aligned}$$

Exercise 6
Solve the following equation. $\begin{aligned} 3(3m-2)=2(3m+3) \end{aligned}$

Answer

$m=4$

Hint

Start with expanding the expressions on both sides.

Solution

We need to find the value of $m$ for which the two sides evaluate to the same number. We start with expanding the expressions on both sides of the equality.

$3(3m-2)=2(3m+3)$

Multiplicera in $3 \ \& \ 2$

$9m-6=6m+6$

Next we use inverse operations to isolate $m.$

$9m-6=6m+6$

$\text{VL}-6m=\text{HL}-6m$

$9m-6m-6=6$

$\text{VL}+6=\text{HL}+6$

$9m-6m=12$

LHS: Bryt ut $m$

$(9-6)m=12$

LHS: Förenkla termer

$3m=12$

$\left.\text{VL}\middle/3\right.=\left.\text{HL}\middle/3\right.$

$m=4$

Hence, the value that makes the equality true is $m=4.$